任亚茹老师的41道C语言机考题答案

发布于 2023-12-31  458 次阅读


  • 提醒:这不是老师给的答案,是我自己弄得,不一定全对(严谨,严谨,严谨)o.0
  • 浏览器 ctrl+f 即可搜索关键词寻找答案
  • 不对的有问题的联系我,我改

求1+2+3+。。。+200的 (while语句)

#include <stdio.h>

int main() {
    int sum = 0;
    int i = 1;
    
    while (i <= 200) {
        sum += i;
        i++;
    }
    
    printf("1+2+3+...+200 = %d\n", sum);
    
    return 0;
}

求1+2+3+。。。+200的 (do while语句)

#include <stdio.h>

int main() {
    int sum = 0;
    int i = 1;
    
    do {
        sum += i;
        i++;
    } while (i <= 200);
    
    printf("1+2+3+...+200 = %d\n", sum);
    
    return 0;
}

求1+2+3+。。。+200的 (for语句)

#include <stdio.h>

int main() {
    int sum = 0;
    
    for (int i = 1; i <= 200; i++) {
        sum += i;
    }
    
    printf("1+2+3+...+200 = %d\n", sum);
    
    return 0;
}

求1+3+5+。。。+99的和 (while语句)

#include <stdio.h>

int main() {
    int sum = 0;
    int i = 1;
    
    while (i <= 99) {
        sum += i;
        i += 2;
    }
    
    printf("1+3+5+...+99 = %d\n", sum);
    
    return 0;
}

求1+3+5+。。。+99的和 (for语句)

#include <stdio.h>

int main() {
    int sum = 0;
    
    for (int i = 1; i <= 99; i += 2) {
        sum += i;
    }
    
    printf("1+3+5+...+99 = %d\n", sum);
    
    return 0;
}

求2+4+6+。。。+100的和 (while语句)

int main() {
    int sum = 0;
    int i = 2;
    
    while (i <= 100) {
        sum += i;
        i += 2;
    }
    
    printf("2+4+6+...+100 = %d\n", sum);
    
    return 0;
}

求2+4+6+。。。+100的和 (do while语句)

#include <stdio.h>

int main() {
    int sum = 0;
    int i = 2;
    
    do {
        sum += i;
        i += 2;
    } while (i <= 100);
    
    printf("2+4+6+...+100 = %d\n", sum);
    
    return 0;
}

求2+4+6+。。。+100的和 (for语句)

#include <stdio.h>

int main() {
    int sum = 0;
    
    for (int i = 2; i <= 100; i += 2) {
        sum += i;
    }
    
    printf("2+4+6+...+100 = %d\n", sum);
    
    return 0;
}

求10的阶乘(while语句)

#include <stdio.h>

int main() {
    int n = 10;
    int factorial = 1;
    
    while (n > 0) {
        factorial *= n;
        n--;
    }
    
    printf("10的阶乘 = %d\n", factorial);
    
    return 0;
}

求10的阶乘 (for语句)

#include <stdio.h>

int main() {
    int n = 10;
    int factorial = 1;
    
    for (int i = 1; i <= n; i++) {
        factorial *= i;
    }
    
    printf("10的阶乘 = %d\n", factorial);
    
    return 0;
}

求10的阶乘(递归法)

#include <stdio.h>

int factorial(int n) {
    if (n == 0) {
        return 1;
    } else {
        return n * factorial(n - 1);
    }
}

int main() {
    int n = 10;
    int result = factorial(n);
    
    printf("10的阶乘 = %d\n", result);
    
    return 0;
}

输入五个数,按从小到大输出 (冒泡法)

#include <stdio.h>
#define N 5

int main() {
    int a[N], i, j, min, t;
    printf("请输入5个数字:\n");
    for (i = 0; i < N; i++)
        scanf("%d", &a[i]);
    for (i = 0; i < N - 1; i++) {
        min = i;
        for (j = i + 1; j < N; j++) {
            if (a[j] < a[min]) { 
                min = j; 
            }
        }
        if (min != i) {
            t = a[i];
            a[i] = a[min];
            a[min] = t;
        }
    }
    printf("从小到大的排序结果为:\n");
    for (i = 0; i < N; i++)
        printf("%d ", a[i]);
    return 0;
}

输出左直角形状的九九乘法口诀

#include <stdio.h>

int main() {
    for (int i = 1; i <= 9; i++) {
        for (int j = 1; j <= i; j++) {
            printf("%d * %d = %d\t", j, i, j * i);
        }
        printf("\n");
    }
    
    return 0;
}

输出右直角形状的九九乘法口诀

#include <stdio.h>

int main() {
    for (int i = 1; i <= 9; i++) {
        for (int j = 1; j <= 9 - i; j++) {
            printf("\t");
        }
        for (int k = 1; k <= i; k++) {
            printf("%d * %d = %d\t", k, i, k * i);
        }
        printf("\n");
    }
    
    return 0;
}

输入四个数,并求最大值

#include <stdio.h>

int main() {
    int num1, num2, num3, num4;
    int max;

    printf("请输入四个数,用空格分隔:");
    scanf("%d %d %d %d", &num1, &num2, &num3, &num4);

    max = num1; 
    if (num2 > max) {
        max = num2;
    }

    if (num3 > max) {
        max = num3;
    }

    if (num4 > max) {
        max = num4;
    }

    printf("最大值为:%d\n", max);

    return 0;
}

输入四个数,并求最小值

#include <stdio.h>

int main() {
    int num1, num2, num3, num4;
    int min;

    printf("请输入四个数,用空格分隔:");
    scanf("%d %d %d %d", &num1, &num2, &num3, &num4);

    min = num1;

    if (num2 < min) {
        min = num2;
    }

    if (num3 < min) {
        min = num3;
    }

    if (num4 < min) {
        min = num4;
    }

    printf("最小值为:%d\n", min);

    return 0;
}

输入三个数,按从大到小输出

#include <stdio.h>

int main() {
    int num1, num2, num3;

    printf("请输入三个数,用空格分隔:");
    scanf("%d %d %d", &num1, &num2, &num3);

    if (num1 < num2) {
        int temp = num1;
        num1 = num2;
        num2 = temp;
    }

    if (num2 < num3) {
        int temp = num2;
        num2 = num3;
        num3 = temp;
    }

    if (num1 < num2) {
        int temp = num1;
        num1 = num2;
        num2 = temp;
    }

    printf("从大到小输出: %d %d %d\n", num1, num2, num3);

    return 0;
}

输入三个数,按从小到大输出

#include <stdio.h>

int main() {
    int num1, num2, num3;

    printf("请输入三个数,用空格分隔:");
    scanf("%d %d %d", &num1, &num2, &num3);

    if (num1 > num2) {
        int temp = num1;
        num1 = num2;
        num2 = temp;
    }

    if (num2 > num3) {
        int temp = num2;
        num2 = num3;
        num3 = temp;
    }

    if (num1 > num2) {
        int temp = num1;
        num1 = num2;
        num2 = temp;
    }

    printf("从小到大输出: %d %d %d\n", num1, num2, num3);

    return 0;
}

输入五个数,按从小到大输出(数组名作为函数参数,冒泡法)

#include <stdio.h>

void bubbleSort(int arr[], int size) {
    int i, j;
    for (i = 0; i < size - 1; i++) {
        for (j = 0; j < size - i - 1; j++) {
            if (arr[j] > arr[j + 1]) {
                int temp = arr[j];
                arr[j] = arr[j + 1];
                arr[j + 1] = temp;
            }
        }
    }
}

int main() {
    int arr[5];
    int i;

    printf("请输入五个数,用空格分隔:");
    for (i = 0; i < 5; i++) {
        scanf("%d", &arr[i]);
    }

    bubbleSort(arr, 5);

    printf("从小到大输出:");
    for (i = 0; i < 5; i++) {
        printf(" %d", arr[i]);
    }
    printf("\n");

    return 0;
}

在主函数中输入五个数,按从小到大输出(调用函数)

#include <stdio.h>

void bubbleSort(int arr[], int size) {
    int i, j;
    for (i = 0; i < size - 1; i++) {
        for (j = 0; j < size - i - 1; j++) {
            if (arr[j] > arr[j + 1]) {
                int temp = arr[j];
                arr[j] = arr[j + 1];
                arr[j + 1] = temp;
            }
        }
    }
}

int main() {
    int arr[5];
    int i;

    printf("请输入五个数,用空格分隔:");
    for (i = 0; i < 5; i++) {
        scanf("%d", &arr[i]);
    }

    bubbleSort(arr, 5);

    printf("从小到大输出:");
    for (i = 0; i < 5; i++) {
        printf(" %d", arr[i]);
    }
    printf("\n");

    return 0;
}

编辑简单的程序,能分别进行加减乘除运算 (if语句)

#include <stdio.h>

int main() {
    double num1, num2, result;
    char operator;

    printf("请输入两个数,用空格分隔:");
    scanf("%lf %lf", &num1, &num2);

    printf("请输入运算符(+、-、*、/):");
    scanf(" %c", &operator);

    if (operator == '+') {
        result = num1 + num2;
        printf("加法运算结果:%.2lf\n", result);
    } else if (operator == '-') {
        result = num1 - num2;
        printf("减法运算结果:%.2lf\n", result);
    } else if (operator == '*') {
        result = num1 * num2;
        printf("乘法运算结果:%.2lf\n", result);
    } else if (operator == '/') {
        if (num2 != 0) {
            result = num1 / num2;
            printf("除法运算结果:%.2lf\n", result);
        } else {
            printf("错误:除数不能为零!\n");
        }
    } else {
        printf("错误:无效的运算符!\n");
    }

    return 0;
}

编辑简单的程序,能分别进行加减乘除运算 (switch语句)

#include <stdio.h>

int main() {
    double num1, num2, result;
    char operator;

    printf("请输入两个数,用空格分隔:");
    scanf("%lf %lf", &num1, &num2);

    printf("请输入运算符(+、-、*、/):");
    scanf(" %c", &operator);

    switch (operator) {
        case '+':
            result = num1 + num2;
            printf("加法运算结果:%.2lf\n", result);
            break;
        case '-':
            result = num1 - num2;
            printf("减法运算结果:%.2lf\n", result);
            break;
        case '*':
            result = num1 * num2;
            printf("乘法运算结果:%.2lf\n", result);
            break;
        case '/':
            if (num2 != 0) {
                result = num1 / num2;
                printf("除法运算结果:%.2lf\n", result);
            } else {
                printf("错误:除数不能为零!\n");
            }
            break;
        default:
            printf("错误:无效的运算符!\n");
            break;
    }

    return 0;
}

编辑简单的程序,能同时进行加减乘除运算 (嵌套调用)

#include <stdio.h>

double add(double num1, double num2) {
    return num1 + num2;
}

double subtract(double num1, double num2) {
    return num1 - num2;
}

double multiply(double num1, double num2) {
    return num1 * num2;
}

double divide(double num1, double num2) {
    if (num2 != 0) {
        return num1 / num2;
    } else {
        printf("错误:除数不能为零!\n");
        return 0;
    }
}

int main() {
    double num1, num2;

    printf("请输入两个数,用空格分隔:");
    scanf("%lf %lf", &num1, &num2);

    printf("加法运算结果:%.2lf\n", add(num1, num2));
    printf("减法运算结果:%.2lf\n", subtract(num1, num2));
    printf("乘法运算结果:%.2lf\n", multiply(num1, num2));
    printf("除法运算结果:%.2lf\n", divide(num1, num2));

    return 0;
}

输入10位同学的成绩 (58,76,80,95,70,65,88,92,68、5
0),判断优秀、良好,及格,不及格 (if else)

#include <stdio.h>

int main() {
    int scores[10];
    int i;

    printf("请输入10位同学的成绩:\n");
    for (i = 0; i < 10; i++) {
        printf("同学%d的成绩:", i + 1);
        scanf("%d", &scores[i]);
    }

    printf("成绩等级:\n");
    for (i = 0; i < 10; i++) {
        printf("同学%d:", i + 1);
        if (scores[i] >= 90) {
            printf("优秀\n");
        } else if (scores[i] >= 80) {
            printf("良好\n");
        } else if (scores[i] >= 60) {
            printf("及格\n");
        } else {
            printf("不及格\n");
        }
    }

    return 0;
}

输入10位同学的成绩 (58,76,80,95,70,65,88,92,68、5
0),判断优秀、良好,及格,不及格 (switch)

#include <stdio.h>

int main() {
    int scores[10];
    int i;

    printf("请输入10位同学的成绩:\n");
    for (i = 0; i < 10; i++) {
        printf("同学%d的成绩:", i + 1);
        scanf("%d", &scores[i]);
    }

    printf("成绩等级:\n");
    for (i = 0; i < 10; i++) {
        printf("同学%d:", i + 1);
        switch (scores[i] / 10) {
            case 10:
            case 9:
                printf("优秀\n");
                break;
            case 8:
                printf("良好\n");
                break;
            case 6:
            case 7:
                printf("及格\n");
                break;
            default:
                printf("不及格\n");
                break;
        }
    }

    return 0;
}

输入10位同学的成绩 (58,76,80,95,70,65,88,92,68、5
0),按照从低到高的顺序输出

#include <stdio.h>

int main() {
    int grades[] = {85, 92, 78, 90, 88, 82, 95, 87, 80, 91};
    int n = sizeof(grades) / sizeof(grades[0]);

    printf("原始成绩:\n");
    for (int i = 0; i < n; i++) {
        printf("%d ", grades[i]);
    }
    printf("\n");

    for (int i = 0; i < n - 1; i++) {
        for (int j = 0; j < n - i - 1; j++) {
            if (grades[j] > grades[j + 1]) {
                int temp = grades[j];
                grades[j] = grades[j + 1];
                grades[j + 1] = temp;
            }
        }
    }

    printf("排序后的成绩:\n");
    for (int i = 0; i < n; i++) {
        printf("%d ", grades[i]);
    }
    printf("\n");

    return 0;
}

输入10位同学的成绩 (58,76,80,95,70,65,88,92,68、5
0),按照从高到低的顺序输出

#include <stdio.h>

int main() {
    int grades[] = {85, 92, 78, 90, 88, 82, 95, 87, 80, 91};
    int n = sizeof(grades) / sizeof(grades[0]);

    printf("原始成绩:\n");
    for (int i = 0; i < n; i++) {
        printf("%d ", grades[i]);
    }
    printf("\n");

    for (int i = 0; i < n - 1; i++) {
        for (int j = 0; j < n - i - 1; j++) {
            if (grades[j] < grades[j + 1]) {
                int temp = grades[j];
                grades[j] = grades[j + 1];
                grades[j + 1] = temp;
            }
        }
    }

    printf("从高到低排序后的成绩:\n");
    for (int i = 0; i < n; i++) {
        printf("%d ", grades[i]);
    }
    printf("\n");

    return 0;
}

输入正方体的棱长,输出其表面积和体积的大小

#include <stdio.h>

int main() {
    float edgeLength;
    printf("请输入正方体的棱长:");
    scanf("%f", &edgeLength);

    float surfaceArea = 6 * edgeLength * edgeLength;
    float volume = edgeLength * edgeLength * edgeLength;

    printf("正方体的表面积为:%.2f\n", surfaceArea);
    printf("正方体的体积为:%.2f\n", volume);

    return 0;
}

有一个3X4矩阵,要求编程输出该矩阵,并求出其中值最大的那个元31素的值,及其所在的行号和列号

#include <stdio.h>

int main() {
    int matrix[3][4] = {
        {5, 8, 12, 3},
        {9, 4, 6, 1},
        {7, 2, 10, 11}
    };

    int maxElement = matrix[0][0];
    int maxRow = 0;
    int maxCol = 0;

    printf("矩阵:\n");
    for (int i = 0; i < 3; i++) {
        for (int j = 0; j < 4; j++) {
            printf("%d ", matrix[i][j]);

            if (matrix[i][j] > maxElement) {
                maxElement = matrix[i][j];
                maxRow = i;
                maxCol = j;
            }
        }
        printf("\n");
    }

    printf("值最大的元素: %d\n", maxElement);
    printf("所在的行号: %d\n", maxRow);
    printf("所在的列号: %d\n", maxCol);

    return 0;
}

当1+2+3+。。。+i的和sum>=100时,输出sum和i的值 (while)

#include <stdio.h>

int main() {
    int i = 1;
    int sum = 0;

    while (sum < 100) {
        sum += i;
        i++;
    }

    printf("满足条件 1+2+3+...+i >= 100 的最小 i 值为:%d\n", i);
    printf("对应的和 sum 为:%d\n", sum);

    return 0;
}

当1+2+3+。。。+i的和sum>=100时,输出sum和i的值 (do while)

#include <stdio.h>

int main() {
    int i = 1;
    int sum = 0;

    do {
        sum += i;
        i++;
    } while (sum < 100);

    printf("满足条件 1+2+3+...+i >= 100 的最小 i 值为:%d\n", i);
    printf("对应的和 sum 为:%d\n", sum);

    return 0;
}

当1+2+3+。。。+i的和sum>=100时,输出sum和i的值 (for)

#include <stdio.h>

int main() {
    int sum = 0;
    int i;

    for (i = 1; sum < 100; i++) {
        sum += i;
    }

    printf("满足条件 1+2+3+...+i >= 100 的最小 i 值为:%d\n", i);
    printf("对应的和 sum 为:%d\n", sum);

    return 0;
}

编写函数,计算x的n次方。在主函数中输入x和n的值,调用该函数,并输出结果

#include <stdio.h>

double power(double x, int n) {
    double result = 1.0;

    if (n >= 0) {
        for (int i = 0; i < n; i++) {
            result *= x;
        }
    } else {
        for (int i = 0; i < -n; i++) {
            result /= x;
        }
    }

    return result;
}

int main() {
    double x;
    int n;

    printf("请输入 x 的值:");
    scanf("%lf", &x);

    printf("请输入 n 的值:");
    scanf("%d", &n);

    double result = power(x, n);

    printf("%.2lf 的 %d 次方结果为:%.2lf\n", x, n, result);

    return 0;
}

利用数组实现: 输入10个整数,找出其中的最大值

#include <stdio.h>

int main() {
    int numbers[10];
    int i, max;

    printf("请输入 10 个整数:\n");

    for (i = 0; i < 10; i++) {
        scanf("%d", &numbers[i]);
    }

    max = numbers[0];

    for (i = 1; i < 10; i++) {
        if (numbers[i] > max) {
            max = numbers[i];
        }
    }

    printf("最大值为:%d\n", max);

    return 0;
}

利用数组实现: 输入一个字符串,然后将其倒序输出

#include <stdio.h>
#include <string.h>

int main() {
    char str[100];
    int length, i;

    printf("请输入一个字符串:\n");
    scanf("%s", str);

    length = strlen(str);

    printf("倒序输出字符串:");
    for (i = length - 1; i >= 0; i--) {
        printf("%c", str[i]);
    }
    printf("\n");

    return 0;
}

编写程序,输入一个年份,判断该年是否是闰年(闺年的判断条件年份能被4整除,并且不能被100整除,或能被400整除)

#include <stdio.h>

int main() {
    int year;

    printf("请输入一个年份:\n");
    scanf("%d", &year);

    if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0) {
        printf("%d 年是闰年。\n", year);
    } else {
        printf("%d 年不是闰年。\n", year);
    }

    return 0;
}

输出所有的水仙花数

#include <stdio.h>
#include <math.h>

int main() {
    int start, end, number, digit, sum;

    printf("请输入要查找的范围(起始和结束数字):\n");
    scanf("%d %d", &start, &end);

    printf("水仙花数:\n");
    for (number = start; number <= end; number++) {
        int temp = number;
        sum = 0;

        while (temp != 0) {
            digit = temp % 10;
            sum += pow(digit, 3);
            temp /= 10;
        }

        if (sum == number) {
            printf("%d\n", number);
        }
    }

    return 0;
}

有如下一组数据:98,12,87、4,65,23,54、33,48,78,利用冒泡排序法将其由小到大排序后输出。

#include <stdio.h>

void bubbleSort(int arr[], int n) {
    int i, j, temp;
    for (i = 0; i < n - 1; i++) {
        for (j = 0; j < n - i - 1; j++) {
            if (arr[j] > arr[j + 1]) {
                temp = arr[j];
                arr[j] = arr[j + 1];
                arr[j + 1] = temp;
            }
        }
    }
}

int main() {
    int arr[] = {98, 12, 87, 4, 65, 23, 54, 33, 48, 78};
    int n = sizeof(arr) / sizeof(arr[0]);

    printf("初始数组:\n");
    for (int i = 0; i < n; i++) {
        printf("%d ", arr[i]);
    }

    bubbleSort(arr, n);

    printf("\n排序后的数组:\n");
    for (int i = 0; i < n; i++) {
        printf("%d ", arr[i]);
    }

    return 0;
}

从键盘上任意输入一个四位整数,分别输出它的个位数、十位数、百位数和千位数

#include <stdio.h>

int main() {
    int number;

    printf("请输入一个四位整数:\n");
    scanf("%d", &number);

    int thousands = number / 1000;
    int hundreds = (number / 100) % 10;
    int tens = (number / 10) % 10;
    int units = number % 10;

    printf("千位数:%d\n", thousands);
    printf("百位数:%d\n", hundreds);
    printf("十位数:%d\n", tens);
    printf("个位数:%d\n", units);

    return 0;
}
  • alipay_img
  • wechat_img
邪王真眼是最强的!!
最后更新于 2024-01-04